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-9p^2+6p+1=2
We move all terms to the left:
-9p^2+6p+1-(2)=0
We add all the numbers together, and all the variables
-9p^2+6p-1=0
a = -9; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-9)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$p=\frac{-b}{2a}=\frac{-6}{-18}=1/3$
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